Q54,paper 3,j13. Hamming distance between 100101000110 and 110111101101 is

(A) 3

(B) 4

(C) 5

(D) 6

Answer D.

Explanation

100101000110

Xor.

110111101101

---------------------

010010101011.

(one represents the different bit in two words.)

Total 6 different bits . hence hamming distance is 6.