Thursday 4 June 2015

Q67,Paper 3,j13 Which one of the following is a correct implementation of the meta- predicate “not” in PROLOG (Here G represents a goal) ?



(A) not(G):– !, call(G), fail.
not(G).
(B) not(G):– call(G), !, fail.
not(G).
(C) not(G):– call(G), fail, !.
not(G).
(D) not(G):– call(G), fail.
not(G):– !.
Answer B.

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