Options A) 8x10 6bytes /sec B) 4x10 6 bytes/sec c) 16x 10 6 bytes/sec
Answer. BExplanation.
Minimum bus cycle duration = 4 clock cycle.
maximum bus cycle rate= 8 MHZ/4= 2M/s where 1 MHZ= 1000000/sec.
maximum data transferred per bus cycle rate= 2bytes.
data transferred rate per second = data transferred per bus cycle* bus cycle rate.= 2bytes*2M/s
4* 106 bytes/sec
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