Q2,P2,J15. Consider an experiment of tossing two fair dice, one black and one red. What is the probability that the number on the black die divides the number on red die?

A)22/36        B)12/36        C)14/36        D)6/36.

Answer C.

Explanation.

Black die can have no  from 1-6 , total 6ways arrangement and red die can be arranged 6 ways.

Total cases= 6x6=36.

If black dice wins 1. Then it divides  all cases of  winning numbers of red dice. (1,2,3,4,5,6 numbers) so total 6 options.

If black dice wins 2. Then it divides    winning numbers of red dice. (2,4,6 numbers) so total 3.

If black dice wins 3. Then it divides  cases of  wining numbers of red dice. (3,6 numbers) so total 2.

If black dice wins 4. Then it divides  cases of  wining numbers of red dice. (4number) so total 1.

If black dice wins 5. Then it divides   cases of  wining numbers of red dice. (5 number) so total 1.

If black dice wins 6. Then it divides   cases of  wining numbers of red dice. (6 number) so total 1.

Total possible cases are (6+3+2+1+1+1)=14

Probability=14/36.