Q1,p2,d14. Consider a set A = {1, 2, 3, ........, 1000}. How many members of A shall be divisible by 3 or by 5 or by both 3 and 5 ?

(A) 533 (B) 599

(C) 467 (D) 66

Answer C.

Explanation.

Number divisible by 3 are 3,6,9----999.  Total numbers are 333.

Numbers divisible by 5 are 5,10,15---1000. Total numbers are 200.

Numbers divisible by 15 are are multiple of 3,5 also so they are repeated twice .

15,30,----990 , there are 66 numbers.

So total numbers are 333+200-66=467.