(A) The binary sum of a code and its
9’s complement is equal to 9.
(B) It is a weighted code.
(C) Complement can be generated by
inverting each bit pattern.
(D) The binary sum of a code and its
10’s complement is equal to 9.
Answer A,C
Explanation.
Excess 3 code is generated by adding
3 and representing in binary form.
0 is represented 011.
1 isrepresented as 100
2
is represented as 101.
3 is represented as 110.
Let take case A. 1 is represented as (100)
9th complement of (100)
is 5 represenetd as (101) its sum is 0100+101=1001.equals to decimal 9.
In another case lets take the code
110.its 9’s complement is 3.
Addition 110+011=1001. Hence option
A is true.
It is not weighted sum.
Self complimenting code produce 9’s
complement on inverting bit.
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