Monday 22 June 2015

Q62,p3,j14. Consider the fractional knapsack



instance n = 4, (p1, p2, p3,, p4) = (10, 10, 12, 18),
 (w1, w2, w3, w4) = (2, 4, 6, 9) and M = 15. The maximum profit is given by (Assume p and w denotes profit and
weight of objects respectively)
(A) 40
(B) 38
(C) 32
(D) 30.

Answer B.

Greedy method.


product
Weight
price
Pi/w1(cost index)
P1
2
10
5
P2
4
10
2.5
P3
6
12
2
P4
9
18
2

Put first the costliest items in bag.
P1(2kg) its value is 10.
P2(4 kg) its value is 10.
P3(6 kg) its value is 12.
P4(3kg) its value is 6.

Total weight =15 and it carries values of worth =38.

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