μA(x) = {0.2, 0.5, 0.6, 0.1, 0.9}
μB(x) = {0.1, 0.5, 0.2, 0.7, 0.8}
Then the value of μA ∩ μB will
be
(A) {0.2, 0.5, 0.6, 0.7, 0.9}
(B) {0.2, 0.5, 0.2, 0.1, 0.8}
(C) {0.1, 0.5, 0.6, 0.1, 0.8}
(D) {0.1, 0.5, 0.2, 0.1, 0.8}
Answer D
Explanation.
μA ∩ μB={min(.2,.1),min(.5,.5),min(.6,.2),min(.1,.7),min(.9,.8)}
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