Q7,paper3, j14. Given U = {1, 2, 3, 4, 5, 6, 7} A = {(3, 0.7), (5, 1), (6, 0.8)} then ~ A will be : (where ~ →complement)

(A) {(4, 0.7), (2, 1), (1, 0.8)}

(B) {(4, 0.3), (5, 0), (6, 0.2) }

(C) {(1, 1), (2, 1), (3, 0.3), (4, 1), (6, 0.2), (7, 1)}

(D) {(3, 0.3), (6.0.2)}

Answer C

Explanation.

 Membership of 3=.7

Membership  of 5=1.

Membership of 6=.8

Membership of 3’=.3

Membership  of 5’=0,

Membership of 6’=.2.

A’  is  universe of discourse set not in Set A.

{(1,1),(2,2),(3,.3),(4,1),(6.2),(7,1)}.