(A) 10 clusters, 24 regions and 20 routers
(B) 12 clusters, 20 regions and 20 routers
(C) 16 clusters, 12 regions and 25 routers
(D) 15 clusters, 16 regions and 20 routers
Explanation.
Assume that there are 'a' clusters,
'b' regions in each region and 'c' routers per region.
And a.b.c=4800. All the
options qualify multiplication.
The formula to minimize is (a - 1) +
(b - 1) + c. eq 1.
Option 1. Eq 1 sums 52.
Option 2, sums 50.
Option 3.sums 51.
Option 4. Sums 49.
Answer D will have to keep minimum
routing table.
good explanation
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