1o1 = 1,
1 o0 = 0,
0 o1=0
and
0 o0 = 1
What will be the truth value of the
expression (x oy)oz = x o(yoz) ?
(A) Always false
(B) Always true
(C) Sometimes true
(D) True when x, y, z are all true .
Answer B.
x
|
y
|
z
|
(x oy)oz = x o(yoz)
|
Result of expr.
|
0
|
0
|
0
|
1.0=0.1->0=0
|
T(0=0)
|
0
|
0
|
1
|
1.1=0.0->1=1
|
T
|
0
|
1
|
0
|
0.0=0.0->1=1
|
T
|
0
|
1
|
1
|
0.1=0.1->0=0
|
T
|
1
|
0
|
0
|
0.0=1.1->1=1
|
T
|
1
|
0
|
1
|
0.1=1.0->0=0
|
T
|
1
|
1
|
0
|
1.0=1.0->0=0
|
T
|
1
|
1
|
1
|
1.1=1.1
|
T
|
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