(A) In 1NF not in 2NF
(B) In 2NF not in 3NF
(C) In 3NF
(D) In 1NF
Answer A.
A relation schema R is in second normal form (2NF).
If every non key attribute A in R is fully functionally dependent on the
primary key.
In R(a,b,c,d)
b->d
a->c.
There is not a single key which derives all the non
key values. Hence it is not in 2nd normal form.
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