x1+ x2+ x3= 11
where x1>=1, x2>=2, x3>=3
(A) C(7, 11)
(B) C(11, 3)
(C) C(14, 11)
(D) C(7, 5)
Explanation
Total number of feasible solutions are
factorial(n)/(factorial(m)*factorial(n-m)).
M i s basic non zero value variable.
C(n,m) are the feasible solutions . we know that m=3 in the problem hence C(11,3) is the answer.
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