(A) xz’+xy+y’z
(B) xz’+xy+y’z’
(C) xz+xy+y’z’
(D) xz+xy’+y’z
Answer(A)
Explanation.
Let z=0 and y=0, at the first mux, X is selected.as y was zero second mux also selects X as function. These values are put in the options.
Option A= x+0+0 . hence A qualifies.
Option B=X+0+1.= 1 hence B fails.
Option C=0+0+1=1 hence C fails.
Option D=0+x+0=x hence D qualifies. Let z=1 and y=0 ,at the first mux . y’ is selected at second mux y’ is selected.values are fitted into the options given below. Option A=0+0+y’
Option D=X+x+1= 1 hence option D also fails.
hence option A is the answer.
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